5(r-7)+2[r-3(r-5)]=0

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Solution for 5(r-7)+2[r-3(r-5)]=0 equation:


Simplifying
5(r + -7) + 2[r + -3(r + -5)] = 0

Reorder the terms:
5(-7 + r) + 2[r + -3(r + -5)] = 0
(-7 * 5 + r * 5) + 2[r + -3(r + -5)] = 0
(-35 + 5r) + 2[r + -3(r + -5)] = 0

Reorder the terms:
-35 + 5r + 2[r + -3(-5 + r)] = 0
-35 + 5r + 2[r + (-5 * -3 + r * -3)] = 0
-35 + 5r + 2[r + (15 + -3r)] = 0

Reorder the terms:
-35 + 5r + 2[15 + r + -3r] = 0

Combine like terms: r + -3r = -2r
-35 + 5r + 2[15 + -2r] = 0
-35 + 5r + [15 * 2 + -2r * 2] = 0
-35 + 5r + [30 + -4r] = 0

Reorder the terms:
-35 + 30 + 5r + -4r = 0

Combine like terms: -35 + 30 = -5
-5 + 5r + -4r = 0

Combine like terms: 5r + -4r = 1r
-5 + 1r = 0

Solving
-5 + 1r = 0

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 1r = 0 + 5

Combine like terms: -5 + 5 = 0
0 + 1r = 0 + 5
1r = 0 + 5

Combine like terms: 0 + 5 = 5
1r = 5

Divide each side by '1'.
r = 5

Simplifying
r = 5

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